**Problem:**

*Hi there!
I have started learning java just recently and
I found a problem in a programming exercise in which I have to find the second largest number in a given array using programming. I know how to find the largest number,
but I am facing difficulty in making the logic for finding the second-largest number.*

*Can anybody here help me solve the problem?
Also, provide the example program so that I can understand it better. Thanks!*

### Solution:

*Hello! The problem you have mentioned is very easy. All you need to do is,
after finding the largest number, apply another logic.*

*However, consider the following code snippet, which will solve your problem.*

**Please refer to the comments to better understand the code:**

```
public class Main
{
public static void main(String[] args) {
int[] arr = {5,3,7,8,2,68,4,19};
int largest = 0, second_largest = 0;
for(int i = 0; i<arr.length; i++)
{
//this condition will keep evaluating unless i is less than the length of array or largest number is not found
if(arr[i] > largest) //if(arr[i] > 0)
{
second_largest = largest; //second_largest = 0
largest = arr[i]; //assigning the largest element of array to 'largest' variable
}
else if(arr[i] > second_largest && arr[i] != largest)//if above condition is false, this will be evaluated in order to find the second largest number
{
second_largest = arr[i];
}
}
System.out.println("Largest:" + largest + "\nSecond largest:" + second_largest);
}
}
```

**Output:**

```
Largest:68
Second largest:19
```

**I hope you found the answer you were looking for, Thanks!**