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0 votes

Problem :

I am facing following error message:

DOMException: Failed to load because no supported source was found in video.play(); line.

I have started getting this issue only after adding following code:

video.setAttribute('crossorigin', 'anonymous');

I am trying to develop an app in the mobile so for the cross origin I must add this line. Also note that I am getting this issue only after the updating my chrome to 50 version before that it was working fine.

<!DOCTYPE html>



       <script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>




     var video = document.createElement( 'video' );

     video.id = 'video';   

     video.type = ' video/mp4; codecs="theora, vorbis" ';  

     video.src = "http://abcde.com/img/videos/what_is_design_thinking.mp4";

     video.volume = .1;

     video.setAttribute('crossorigin', 'anonymous');   

     video.load(); // must call after setting/changing source  



     var canvas = document.createElement('canvas');

     var ctx = canvas.getContext('2d');


     video.addEventListener('play', function() {

       var $this = this; //cache

       (function loop() {

       if (!$this.paused && !$this.ended) {

       ctx.drawImage($this, 0, 0);

       setTimeout(loop, 1000 / 30); // drawing at 30fps



      }, 0);




7.5k points

1 Answer

0 votes

Solution :

I had the same error in the recent past and it turned out to be a CORS issue.

So instead of below code:

video.setAttribute('crossorigin', 'anonymous'); 

Try the below correct code:

video.crossOrigin = 'anonymous';

And also please make sure that the server response must have the header as Access-Control-Allow-Origin:*. Instead of the asterisk wild card, you can specify the domain of the website that is allowed to access your video from the server.

36.1k points

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