• Register
0 votes

Problem :

I am currently facing below error in my iPhone:

“The maximum number of free accounts have been activated on this iPhone”.

To fix this problem I even tried to erase all content and settings of the iPhone and after that set it as the fresh new iPhone.

But I am still facing the above problem.

How can I fix my iPhone now?

8 4 2
2,300 points

Please log in or register to answer this question.

1 Answer

0 votes

Solution :

I have read your question. I am trying to help you.

Please note that the Apple currently limits all its iDevice products to the maximum number of free accounts up to 3 total iCloud accounts per your iDevice. Any one iDevice can create up to the maximum of 3 iCloud accounts and then these accounts are tied to the iDevice hardware, not the user account i.e. they are now attaching the restriction to the iDevice itself. So now you can not create another iCloud account on your iPhone or the another iDevice. Now this is a Apple hard rule so you can not work around this set limit. If by chance you already created all of your 3 iCloud accounts then in that case you can not create another iCloud account using your particular device.

5 2 1
4,980 points

Related questions

1 vote
2 answers 164 views
Problem : I have very recently purchased my new iPhone. Now want to sync my iphone with the itunes. But I keep on getting below error : Itunes could not connect to this iphone. you do not have permission. I have also tried to read some of the solutions on it of ... I have spent lot of time in fixing above error but unable to fix it as of now so looking for expert help in fixing above error.
asked Apr 21, 2020 stewart 4k points
0 votes
1 answer 704 views
Problem : Facing following Swift issue must register a nib or a class for the identifier or connect a prototype cell in a storyboard
asked Nov 15, 2019 peterlaw 6.9k points
1 vote
1 answer 273 views
Problem: The maximum number of entry points that any programming structure can have is ____.? Which answer fits in the blank? A) five B) zero C) three D) one
asked Feb 19, 2020 maddi86 5.4k points
0 votes
1 answer 175 views
Problem : Xcode as of 6.3 is no longer allowing me to automatically perform the device provisioning for one of my client. Has anybody faced the same issue before? My client has their own bundle ID and it is also the possibility that they may also ... being used for provisioning. I had the workaround for this issue by modifying the app bundle ID and manually completing the provisioning process.
asked Dec 2, 2019 alecxe 7.5k points
0 votes
1 answer 8.5K views
Problem : When going to one of the Facebook page: I face the below message: This page isn't available The link you followed may be broken, or the page may have been removed I seriously want to claim the name of that page for my facebook page, but I don't know what a message means, or if I can even claim the page?
asked Feb 3, 2020 jwilliam 3.9k points
0 votes
1 answer 38 views
Problem : I want to run the NVCC to compile my CUDA program on my Mac. But when I try to run the NVCC, I am facing below error message: "nvcc fatal : The version ('70300') of the host compiler ('Apple clang') is not supported". I tried updating the XCode version to 7.3, and the Mac version to 10.11.4. But I am facing the same error. How can I revert my Apple Clang Version?
asked Nov 30, 2019 alecxe 7.5k points
0 votes
2 answers 24 views
Problem: One of the Windows workstations you manage has three user accounts defined on it. Two of the users are limited users while the third (you account) is an administrative user. Each limited and administrative user has been assigned a strong password. File and ... been assigned to prevent users from accessing each other's files. What else could you do to increase the security of this system?
asked Mar 9, 2020 ArifulIslam 5.6k points
0 votes
1 answer 57 views
Problem : I am trying to retrieve the phone number from my Firebase database, but no matter how I enter it into my database it returns an error on my device as follows: "Message sent to invalid destination. Please check your number and try again. Msg 2127" The ... { // UIApplication.shared.openURL(url as URL) UIApplication.shared.open(urlph as URL, options: [:], completionHandler: nil) } } }
asked Dec 9, 2019 alecxe 7.5k points