# typeerror: 'float' object cannot be interpreted as an integer

1 vote
69 views

## Problem:

Here is my sample code below

``````from turtle import *

speed(0)
hideturtle()
c = 450

def grid(x,y,a):
seth(0)
pu()
goto(x,y)
pd()
for i in range(4):
forward(a)
rt(90)
for i in range(c/10):
seth(0)
forward(10)
rt(90)
forward(c)
backward(c)
for i in range(c/10):
seth(0)
rt(90)
forward(10)
rt(90)
forward(c)
backward(c)
pu()
goto(a+10,0)
write("x")
goto(0,a+10)
write("y")
pd()

grid(0,0,c)
grid(-c,0,c)
grid(-c,c,c)
grid(0,c,c)``````

And I am getting this error message

``````Traceback (most recent call last):
File "C:\Users\nick\Desktop\gridv2.py", line 35, in <module>
grid(0,0,c)
File "C:\Users\nick\Desktop\gridv2.py", line 15, in grid
for i in range(c/10):
TypeError: 'float' object cannot be interpreted as an integer``````

What’s wrong with my code?

1 vote

## Solution:

Here, `c/10` is a float number because `/` always returns a float number.

Make the value an integer again:

``for i in range(int(c / 10)):``

You may also (//) the floor division operator to make it an integer number.

``for i in range(c // 10):``