# Which ordered pair maximizes the objective function p = 3x + 8y?

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## Problem:

Which ordered pair maximises the objective function P = 3x + 8y?
(0, 0)
(2, 7)
(5, 6)
(8, 1)

## Solution:

Substitute each of those ordered pairs in until you get the largest number so: (0,0)=3(0)+8(0)=0

(2,7)=3(2)+8(7)=62

(5,6)=3(5)+8(6)=63

(8,1)=3(8)+8(1)=42

SO the answer would be (5,6)

### Explanation:

Ordered pairs in this set are used to evaluate the objective function to determine which ordered pair maximizes the profit. The objective function is a mathematical optimization problem is a real-valued function whose value is to be either minimized or maximized over the set of feasible alternatives. Optimization methods are techniques that enable us to solve optimization problems. For this, it is necessary to optimize the working of a system, minimizing or maximizing one of its many objectives or performance criteria.

## Solution:

The Correct Answer of this question is ( 5,6)

### Explanation:

Substitute each of those ordered pairs in until you get the largest number so: (0,0)=3(0)+8(0)=0

(2,7)=3(2)+8(7)=62

(5,6)=3(5)+8(6)=63

(8,1)=3(8)+8(1)=42

SO the answer would be (5,6)

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