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2 votes
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Problem:

I am trying a run a program with a simple list object in my code. But it throwing the same error again and again. The error is: list object cannot be interpreted as an integer python.

I am attaching my code snippet below:

def userNum(iterations):
  testList = []
  for i in range(iterations):
    a = int(input("Enter a number for sound: "))
    testList.append(a)
    return testList
  print(testList)

def playSound(testList):
  for i in range(testList):
    if i == 1:
      winsound.PlaySound("SystemExit", winsound.SND_ALIAS)

What could be the possible solution for this program? If possible figure the error, please.

Thanks

12 7 7
15,250 points

1 Answer

2 votes

Solution:

Every time you get the error from the compiler or the interpreter you should read it carefully. The error clearly says that you did something that’s the reason the interpreter couldn’t interpret the object as an Integer.

So, where are you wrong? The range() is expecting an integer argument, from which it will build a range of integers. You can’t put a list inside the range(), it can’t handle the list.

So, if you want to access the items in testList, loop over the list directly, just use:

>>> testList [1,2,3,4]
>>> for i in myList:
    print (i)

I hope you get the point. Thanks.

13 9 6
94,240 points

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