Answer:
To remove element from list python by index. Supose you want to remove the number 22 from your list use:
listOfnumbers.remove(22)
If you have any other query you can go and check:
https://thispointer.com/python-how-to-remove-element-from-a-list-by-value-or-index-remove-vs-pop-vs-del/
Or use the code :
listOfnumbers = [16, 22, 96, 15, 4, 39, 56, 40, 13, 22, 15]
print("****list.remove()****")
print("Original List : " , listOfnumbers)
listOfnumbers.remove(22)
print("Modified List : " , listOfnumbers)
try :
listOfnumbers.remove(100)
except ValueError:
print("Given Element Not Found in List")
if 99 in listOfnumbers:
listOfnumbers.remove(99)
else:
print("Given Element Not Found in List")
print("*****list.pop()*****")
listOfnumbers = [12, 44, 12, 56, 45, 34, 3, 56, 4, 33, 44, 56]
print("Original List : ", listOfnumbers)
value = listOfnumbers.pop(2)
print("Deleted Element : ", value)
print("Modified List : ", listOfnumbers)
value = listOfnumbers.pop()
print("Deleted Element : ", value)
print("Modified List : ", listOfnumbers)
if len(listOfnumbers) >= 20:
listOfnumbers.pop(20)
else:
print("Index Out of Range")
t
try :
listOfnumbers.pop(20)
except IndexError:
print("Index Out of Range")
print("*****del list[index]*****")
listOfnumbers = [12, 44, 56, 45, 34, 3, 4, 33, 44]
print("Original List : ", listOfnumbers)
del listOfnumbers[2]
print("Modified List : ", listOfnumbers)
if len(listOfnumbers) >= 20:
del listOfnumbers[20]
else:
print("Index Out of Range")
try :
del listOfnumbers[20]
except IndexError:
print("Index Out of Range")
if __name__ == '__main__':
main()
